Apostol.Chapter_I_03 #
A Set of Axioms for the Real-Number System
The least-upper-bound axiom (completeness axiom) #
The upper bounds of the negation of a set is the negation of the lower bounds of the set.
The negation of the upper bounds of a set is the lower bounds of the negation of the set.
An element x
is the least element of the negation of a set iff -x
is the
greatest element of the set.
Theorem I.27 #
Every nonempty set S
that is bounded below has a greatest lower bound; that
is, there is a real number L
such that L = inf S
.
Every real should be less than or equal to the absolute value of its ceiling.
The Archimedean property of the real-number system #
Fundamental properties of the supremum and infimum #
Every member of a set S
is less than or equal to some value ub
if and only
if ub
is an upper bound of S
.
Any member of the upper bounds of a set must be greater than or equal to the least member of that set.
Every member of a set S
is greater than or equal to some value lb
if and
only if lb
is a lower bound of S
.
Any member of the lower bounds of a set must be less than or equal to the greatest member of that set.
Theorem I.33a (Additive Property) #
Given nonempty subsets A
and B
of ℝ
, let C
denote the set
C = {a + b : a ∈ A, b ∈ B}
. If each of A
and B
has a supremum, then C
has a supremum, and sup C = sup A + sup B
.
Theorem I.33b (Additive Property) #
Given nonempty subsets A
and B
of ℝ
, let C
denote the set
C = {a + b : a ∈ A, b ∈ B}
. If each of A
and B
has an infimum, then C
has an infimum, and inf C = inf A + inf B
.
Theorem I.34 #
Given two nonempty subsets S
and T
of ℝ
such that s ≤ t
for every s
in
S
and every t
in T
. Then S
has a supremum, and T
has an infimum, and
they satisfy the inequality sup S ≤ inf T
.
Exercise 4 #
If x
is an arbitrary real number, prove that there is exactly one integer n
which satisfies the inequalities n ≤ x < n + 1
. This n
is called the
greatest integer in x
and is denoted by ⌊x⌋
. For example, ⌊5⌋ = 5
,
⌊5 / 2⌋ = 2
, ⌊-8/3⌋ = -3
.
Exercise 6 #
If x
and y
are arbitrary real numbers, x < y
, prove that there exists at
least one rational number r
satisfying x < r < y
, and hence infinitely many.
This property is often described by saying that the rational numbers are dense
in the real-number system.
TODO #
Exercise 7 #
If x
is rational, x ≠ 0
, and y
irrational, prove that x + y
, x - y
,
xy
, x / y
, and y / x
are all irrational.
TODO #
Exercise 9 #
If x
and y
are arbitrary real numbers, x < y
, prove that there exists at
least one irrational number z
satisfying x < z < y
, and hence infinitely
many.
TODO #
Exercise 10 #
An integer n
is called even if n = 2m
for some integer m
, and odd if
n + 1
is even. Prove the following statements:
(a) An integer cannot be both even and odd.
(b) Every integer is either even or odd.
(c) The sum or product of two even integers is even. What can you say about the sum or product of two odd integers?
(d) If n²
is even, so is n
. If a² = 2b²
, where a
and b
are integers,
then both a
and b
are even.
(e) Every rational number can be expressed in the form a / b
, where a
and
b
are integers, at least one of which is odd.
TODO #
Equations
- Apostol.Chapter_I_03.isEven n = ∃ (m : ℤ), n = 2 * m
Instances For
Equations
Instances For
Exercise 11 #
Prove that there is no rational number whose square is 2
.
[Hint: Argue by contradiction. Assume (a / b)² = 2
, where a
and b
are
integers, at least one of which is odd. Use parts of Exercise 10 to deduce a
contradiction.]
TODO #
Exercise 12 #
The Archimedean property of the real-number system was deduced as a consequence of the least-upper-bound axiom. Prove that the set of rational numbers satisfies the Archimedean property but not the least-upper-bound property. This shows that the Archimedean property does not imply the least-upper-bound axiom.